Javascript: The Confuse About Comparison "2 == True"

Here is a javascript comparison: 2 == true //false it's said, the reason why return false, is because the comparison convert the true to Number datatype, and result is 1: console.

Solution 1:

I find the doc here:

Comparison Operators, which said:

If the two operands are not of the same type, JavaScript converts the operands then applies strict comparison. If either operand is a number or a boolean, the operands are converted to numbers if possible; else if either operand is a string, the other operand is converted to a string if possible. If both operands are objects, then JavaScript compares internal references which are equal when operands refer to the same object in memory.

Solution 2:

== does implicit conversion to compare. In this case 2 is number and true is boolean. The conversion rule is "while comparing a number to boolean, boolean will be converted to number" hence

true is converted to 1

and 2 == 1 will be false.

//similarly, 
2 == false; //false

As false will be converted to 0 and 2 cannot be equal to 0 either.

However, 1 == true. for the same reason as true would be converted to 1 and 1==1